Compound 90° Around a Rectangular Obstruction
Quick answer
A compound 90° around a rectangular obstruction, such as a box or cabinet sitting square in the corner, uses two 45° bends joined by a chamfer that passes just outside the obstruction’s far corner. Chamfer = 1.4 × (length + height), corner to corner; the exact factor is 1.414. Between bends = chamfer − the gain of one 45° bend.
A compound 90 turns a corner with two 45° bends instead of one 90, cutting across the corner in front of something that sits in it. This screen is for a rectangular obstruction, such as a box or cabinet, sitting square in the corner.
What to measure
- Stub length: from the end of the conduit to the back of the other leg, as for a 90.
- Obstruction length along the leg and Obstruction height up the stub: the rectangle’s two sides, each measured from the corner.
- Other leg (optional): from the other end to the back of the stub. With it you get the Cut length.
- First bend or Between bends (optional): when the first bend has to go somewhere in particular, or the chamfer has to be a set length, type it in and the other follows. Clearance then shows whether the conduit still clears the obstruction; leave the obstruction blank if there isn’t one.
How to bend it
- Mark the First mark from the stub end, and the second mark Between bends further along.
- Put the first mark on the arrow with the hook facing the stub end, and bend 45°.
- Slide to the second mark and bend another 45° the same way, with the hook still facing the stub end, so the two make 90°.
- Check that the stub and leg are square to each other and both bends are in one plane.
Where the numbers come from
The two 45s are joined by a straight chamfer that passes just outside the rectangle’s far corner. Its length from corner to corner (where the straight lines would meet) is 1.4 × the two sides added together. The rest is the same radius math as any other bend.
chamfer = 1.4 × (length + height)between bends = chamfer − g(45°)first mark = stub − OD/2 − chamfer ÷ √2 − setback(45°) − start of bend- Stub length
- 48"
- Obstruction length along the leg
- 12"
- Obstruction height up the stub
- 18"
- Other leg
- 48"
- First mark
- 15 3/4" (18 5/16" by multiplier)
- Between bends
- 41 13/16" (42" by multiplier)
- Cut length
- 77 9/16"
The chamfer doesn’t allow for the conduit’s own size, and the 1.4 is rounded down from 1.414, so the fit is tight: in this example the conduit would come about 1/16" into the obstruction’s far corner, and the bend shows orange with a negative Clearance. Adding about 1% to the sizes you enter opens up a gap.
If it turns orange or red
Red means the stub or the leg is too short for the chamfer, so a bend would run off the end of the conduit. Orange or red can also mean the two 45s are too close together for the shoe, which only happens with a very small obstruction. Orange also shows when the conduit would touch the obstruction (a negative Clearance), or when the cut length is longer than one stick.
Get the marks for your bender
BendMate works this out from your bender’s radius and deduct, flags a bend that won’t work, and shows you every mark.
Common questions
What is the chamfer for a compound 90 around a box?
Add the obstruction’s length along the leg and its height up the stub, each measured from the corner, and multiply by 1.4. A 12" by 18" obstruction gives 42" between bends by the multiplier method, or 41 13/16" on a 1/2" EMT hand bender.
Why does my compound 90 hit the corner of the box?
The chamfer doesn’t allow for the conduit’s size, and 1.4 is rounded down from 1.414, so the fit is tight: with a 12" by 18" obstruction and 1/2" EMT, the conduit comes about 1/16" into the far corner. Adding about 1% to the sizes you enter opens up a gap.
Where is the first mark on a compound 90 around a box?
First mark = stub − OD/2 − chamfer ÷ √2 − setback(45°) − start of bend, for the arrow. With a 48" stub around a 12" by 18" obstruction on a 1/2" EMT hand bender it is 15 3/4" (18 5/16" by the multiplier method).